MHT CET · Chemistry · Chemical Kinetics
What is rate constant of a first order reaction if \(60 \%\) reactant decompose in 45 minute?
- A 0.010 minute \(^{-1}\)
- B 0.015 minute \(^{-1}\)
- C 0.020 minute \(^{-1}\)
- D 0.025 minute \(^{-1}\)
Answer & Solution
Correct Answer
(C) 0.020 minute \(^{-1}\)
Step-by-step Solution
Detailed explanation
If \([\mathrm{A}]_0=100\), then \([A]_t=100-60=40\)
For a first order reaction,
\(\begin{aligned}
\mathrm{k} & =\frac{2.303}{\mathrm{t}} \log _{10} \frac{[\mathrm{~A}]_0}{[\mathrm{~A}]_{\mathrm{t}}} \\
& =\frac{2.303}{45 \mathrm{~min}} \log _{10} \frac{100}{40} \\
\therefore \quad & =\frac{2.303 \times 0.397}{45 \mathrm{~min}} \\
& =0.020 \text { minute }^{-1}
\end{aligned}\)
For a first order reaction,
\(\begin{aligned}
\mathrm{k} & =\frac{2.303}{\mathrm{t}} \log _{10} \frac{[\mathrm{~A}]_0}{[\mathrm{~A}]_{\mathrm{t}}} \\
& =\frac{2.303}{45 \mathrm{~min}} \log _{10} \frac{100}{40} \\
\therefore \quad & =\frac{2.303 \times 0.397}{45 \mathrm{~min}} \\
& =0.020 \text { minute }^{-1}
\end{aligned}\)
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