MHT CET · Chemistry · Ionic Equilibrium
What is pH of a centimolar solution of \(\mathrm{H}_2 \mathrm{SO}_4\) ?
- A 1.7
- B 2
- C 3.2
- D 4.5
Answer & Solution
Correct Answer
(A) 1.7
Step-by-step Solution
Detailed explanation
\({\left[\mathrm{H}_2 \mathrm{SO}_4\right]=2 \times \mathrm{C}=2 \times 0.01 \mathrm{M}=2 \times 10^{-2} \mathrm{M} } \)
\( \mathrm{pH} =-\log _{10}\left[\mathrm{H}^{+}\right]=-\log _{10}\left[2 \times 10^{-2}\right] \)
\( =-\log _{10} 2-\log _{10} 10^{-2} \)
\( =-\log _{10} 2+2 \)
\( \therefore \mathrm{pH} =2-0.3010=1.7\)
\( \mathrm{pH} =-\log _{10}\left[\mathrm{H}^{+}\right]=-\log _{10}\left[2 \times 10^{-2}\right] \)
\( =-\log _{10} 2-\log _{10} 10^{-2} \)
\( =-\log _{10} 2+2 \)
\( \therefore \mathrm{pH} =2-0.3010=1.7\)
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