MHT CET · Chemistry · Some Basic Concepts of Chemistry
What is percentage atom economy during conversion of reactant to product if formula weight of reactants is \(246 \mathrm{u}\) and of product is \(123 \mathrm{u}\) ?
- A \(40.00 \%\)
- B \(50.00 \%\)
- C \(47.00 \%\)
- D \(21.5 \%\)
Answer & Solution
Correct Answer
(B) \(50.00 \%\)
Step-by-step Solution
Detailed explanation
Atom economy is the conversion efficiency of a chemical process in terms of all atoms involved and the desired products produced.
\(\% \text { Atom economy }\) \(=\frac{\text { Formula weight of desired product }}{\text { Sum of formula weight of allreactant }} \times 100 \)
\( =\frac{123}{246} \times 100 \)
\( =50 \%\)
\(\% \text { Atom economy }\) \(=\frac{\text { Formula weight of desired product }}{\text { Sum of formula weight of allreactant }} \times 100 \)
\( =\frac{123}{246} \times 100 \)
\( =50 \%\)
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