MHT CET · Chemistry · Electrochemistry
What is percent dissociation of \(\mathrm{NH}_4 \mathrm{OH}\) if molar conductance at zero concentration for \(\mathrm{NH}_4 \mathrm{Cl}, \mathrm{NaCl}\) and NaOH are 130,109 and \(213 \mathrm{~S} \mathrm{~cm}^2 \mathrm{~mol}^{-1}\) respectively and molar conductivity of \(0.01 \mathrm{M} \mathrm{NH}_4 \mathrm{OH}\) is \(9.0 \mathrm{~S} \mathrm{~cm}^2 \mathrm{~mol}^{-1}\) ?
- A \(\frac{100}{40}\)
- B \(\frac{100}{35}\)
- C \(\frac{100}{32}\)
- D \(\frac{100}{26}\)
Answer & Solution
Correct Answer
(D) \(\frac{100}{26}\)
Step-by-step Solution
Detailed explanation
\( \Lambda_{m}^{\infty}(\mathrm{NH}_4 \mathrm{OH}) = \Lambda_{m}^{\infty}(\mathrm{NH}_4 \mathrm{Cl}) + \Lambda_{m}^{\infty}(\mathrm{NaOH}) - \Lambda_{m}^{\infty}(\mathrm{NaCl}) \) \( \Lambda_{m}^{\infty}(\mathrm{NH}_4 \mathrm{OH}) = 130 + 213 - 109 = 234 \mathrm{~S} \mathrm{~cm}^2 \mathrm{~mol}^{-1} \)
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