MHT CET · Chemistry · Chemical Equilibrium
What is percent dissociation of acetic acid in it's \(0.01 \mathrm{M}\) solution if dissociation constant of acid is \(1.34 \times 10^{-6}?\)
- A \(13.4 \%\)
- B \(4.02 \%\)
- C \(2.68 \%\)
- D \(1.15 \%\)
Answer & Solution
Correct Answer
(D) \(1.15 \%\)
Step-by-step Solution
Detailed explanation

\(\begin{aligned} & \mathrm{K}_{\mathrm{a}}=\frac{\mathrm{C} \alpha^2}{1-\alpha} \quad 1-\alpha \simeq 1 \\ & \mathrm{~K}_{\mathrm{a}}=\mathrm{Co}^2 \\ & \alpha=\sqrt{\frac{\mathrm{K}_{\mathrm{a}}}{\mathrm{C}}} \\ & \% \alpha=\sqrt{\frac{\mathrm{K}_{\mathrm{a}}}{\mathrm{C}}} \times 100=\sqrt{\frac{1.34 \times 00^{-6}}{0.01}} \times 100 \\ & =1.15 \% \\ & \end{aligned}\)
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