MHT CET · Chemistry · Solutions
What is osmotic pressure of solution of \(1.7 \mathrm{~g} \mathrm{CaCl}_2\) in \(1.25 \mathrm{dm}^3\) water at \(300 \mathrm{~K}\) if van't Hoff factor and molar mass of \(\mathrm{CaCl}_2\), are 2.47 and \(111 \mathrm{~g} \mathrm{~mol}^{-1}\) respectively?
\(\left[\mathrm{R}=0.082 \mathrm{dm}^3 \text { atm mol }{ }^{-1} \mathrm{~K}^{-1}\right]\)
- A \(0.625 \mathrm{~atm}\)
- B \(0.744 \mathrm{~atm}\)
- C \(0.827 \mathrm{~atm}\)
- D \(0.936 \mathrm{~atm}\)
Answer & Solution
Correct Answer
(B) \(0.744 \mathrm{~atm}\)
Step-by-step Solution
Detailed explanation
\(\pi=\mathrm{iMRT}=\frac{\mathrm{i} \times \mathrm{W}_2 \mathrm{RT}}{\mathrm{M}_2 \mathrm{~V}}\)
\(\pi=\frac{2.47 \times 1.7 \mathrm{~g} \times 0.082 \mathrm{dm}^3 \mathrm{~atm} \mathrm{~mol} \mathrm{~K}^{-1} \times 300 \mathrm{~K}}{111 \mathrm{~g} \mathrm{~mol}^{-1} \times 1.25 \mathrm{dm}^3}\)
\(=0.744 \mathrm{~atm}\)
\(\pi=\frac{2.47 \times 1.7 \mathrm{~g} \times 0.082 \mathrm{dm}^3 \mathrm{~atm} \mathrm{~mol} \mathrm{~K}^{-1} \times 300 \mathrm{~K}}{111 \mathrm{~g} \mathrm{~mol}^{-1} \times 1.25 \mathrm{dm}^3}\)
\(=0.744 \mathrm{~atm}\)
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