ExamBro
ExamBro
MHT CET · Chemistry · Some Basic Concepts of Chemistry

What is number of atoms present in \(2.24 \mathrm{dm}^3 \mathrm{NH}_{3(\mathrm{~g})}\) at STP?

  1. A \(6.022 \times 10^{22}\)
  2. B \(2.4088 \times 10^{23}\)
  3. C \(1.8066 \times 10^{22}\)
  4. D \(6.022 \times 10^{23}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(2.4088 \times 10^{23}\)

Step-by-step Solution

Detailed explanation

\(\text {For } \mathrm{NH}_3 \)
\( 22.4 \mathrm{dm}^3 =1 \mathrm{~mol} \)
\( =6.022 \times 10^{22} \text { molecules } \)
\( =6.022 \times 10^{22} \times 4 \text { atoms } \)
\( \therefore 2.24 \mathrm{dm}^3 =0.1 \mathrm{~mol} \)
\( =0.6022 \times 10^{22} \text { molecules } \)
\( =0.6022 \times 10^{22} \times 4 \text { atoms } \)
\( =2.4088 \times 10^{23} \text { atoms }\)