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MHT CET · Chemistry · Solutions

What is Henry's law constant if solubility of a gas in water at \(298 \mathrm{~K}\) and 1 bar pressure is \(7 \times 10^{-4} \mathrm{~mol} \mathrm{~L}^{-1}\)

  1. A \(2.0 \times 10^{-5} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{bar}^{-1}\)
  2. B \(7.0 \times 10^{-4} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{bar}^{-1}\)
  3. C \(3.5 \times 10^{-3} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{bar}^{-1}\)
  4. D \(3.1 \times 10^{-5} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{bar}^{-1}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(7.0 \times 10^{-4} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{bar}^{-1}\)

Step-by-step Solution

Detailed explanation

Solubility \(=\mathrm{K}_{\mathrm{H}} \times\) pgas \(7 \times 10^{-4} \mathrm{~mol} \mathrm{~L}^{-1}=\mathrm{K}_{\mathrm{H}} \times 1\) bar \(\mathrm{K}_{\mathrm{H}}=7 \times 10^{-4} \mathrm{~mol} \mathrm{~L}^{-1} \cdot \mathrm{bar}^{-1}\)