MHT CET · Chemistry · Chemical Kinetics
What is half-life of a first order reaction if time required to decrease concentration of reactant from \(0.8 \mathrm{~mol} \mathrm{dm}^{-3}\) to \(0.2 \mathrm{~mol} \mathrm{dm}^{-3}\) is 12 hour?
- A 6 hour
- B 3 hour
- C 1.5 hour
- D 12 hour
Answer & Solution
Correct Answer
(A) 6 hour
Step-by-step Solution
Detailed explanation
If conc. decreases from \(0.8 \frac{\mathrm{mol}}{\mathrm{dm}^3}\) to \(0.2 \frac{\mathrm{mol}}{\mathrm{dm}^3}\) it means \(75 \%\) of reactant is consumed
\(\therefore \mathrm{t}_{75 \%}=2 \times \mathrm{t}_{1 / 2}\)
\(\text { or } \mathrm{t}_{1 / 2}=6 \mathrm{hr}\)
\(\therefore \mathrm{t}_{75 \%}=2 \times \mathrm{t}_{1 / 2}\)
\(\text { or } \mathrm{t}_{1 / 2}=6 \mathrm{hr}\)
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