MHT CET · Chemistry · Electrochemistry
What happens to the emf for the cell , \({ }^{\ominus} \mathrm{Zn}_{(\mathrm{s})}\left|\mathrm{Zn}^{+2}(1 \mathrm{M})\right|\left|\mathrm{Ag}^{+1}(1 \mathrm{M})\right| \stackrel{\oplus}{\mathrm{Ag}}_{(\mathrm{s})}\) if concentration of \(\mathrm{Ag}^{+1}\) decreases to 0.1 M ?
- A increase by 0.0592 V
- B decrease by 0.0592 V
- C increase by 0.0296 V
- D decrease by 0.0296 V
Answer & Solution
Correct Answer
(B) decrease by 0.0592 V
Step-by-step Solution
Detailed explanation
\(E_{cell} = E^0_{cell} - \frac{0.0592}{n} \log \frac{[\mathrm{Zn}^{+2}]}{[\mathrm{Ag}^{+1}]^2}\) \(\Delta E = E_{final} - E_{initial} = \left(E^0_{cell} - \frac{0.0592}{2} \log \frac{1}{(0.1)^2}\right) - \left(E^0_{cell} - \frac{0.0592}{2} \log \frac{1}{1^2}\right)\)
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