MHT CET · Chemistry · Solid State
What are the number of octahedral and tetrahedral voids in 0.3 mole substance respectively if it forms hcp structure?
- A \(1.8066 \times 10^{23}\) and \(3.6132 \times 10^{23}\)
- B \(3.6132 \times 10^{23}\) and \(1.8066 \times 10^{23}\)
- C \(6.022 \times 10^{23}\) and \(12.044 \times 10^{23}\)
- D \(12.044 \times 10^{23}\) and \(6.022 \times 10^{23}\)
Answer & Solution
Correct Answer
(A) \(1.8066 \times 10^{23}\) and \(3.6132 \times 10^{23}\)
Step-by-step Solution
Detailed explanation
Number of atoms in \(0.3 \mathrm{~mol}\)
\(
\begin{aligned}
& =0.3 \times \mathrm{N}_{\mathrm{A}} \\
& =0.3 \times 6.022 \times 10^{23} \\
& =1.8066 \times 10^{23}
\end{aligned}
\)
i. For hep structure, Number of octahedral voids
\(=\) Number of atoms
\(
=1.8066 \times 10^{23}
\)
ii. For hcp structure, Number of tetrahedral voids
\(
\begin{aligned}
& =2 \times \text { Number of atoms } \\
& =2 \times 1.8066 \times 10^{23} \\
& =3.6132 \times 10^{23}
\end{aligned}
\)
\(
\begin{aligned}
& =0.3 \times \mathrm{N}_{\mathrm{A}} \\
& =0.3 \times 6.022 \times 10^{23} \\
& =1.8066 \times 10^{23}
\end{aligned}
\)
i. For hep structure, Number of octahedral voids
\(=\) Number of atoms
\(
=1.8066 \times 10^{23}
\)
ii. For hcp structure, Number of tetrahedral voids
\(
\begin{aligned}
& =2 \times \text { Number of atoms } \\
& =2 \times 1.8066 \times 10^{23} \\
& =3.6132 \times 10^{23}
\end{aligned}
\)
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