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MHT CET · Chemistry · Solutions

Weak acid HX has dissociation constant \(1 \times 10^{-5}\). Calculate the percent dissociation in its \(0.1 \mathrm{M}\) solution.

  1. A \(2.2 \%\)
  2. B \(3.5 \%\)
  3. C \(4.2 \%\)
  4. D \(1.0 \%\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(1.0 \%\)

Step-by-step Solution

Detailed explanation

\(\mathrm{K}_{\mathrm{a}}=1 \times 10^{-5}, \mathrm{c}=0.1 \mathrm{M} \)
\( \mathrm{K}_{\mathrm{a}} =\alpha^2 \mathrm{c} \)
\( \therefore \alpha =\sqrt{\frac{\mathrm{K}_{\mathrm{a}}}{\mathrm{c}}}=\sqrt{\frac{1 \times 10^{-5}}{0.1}}=\sqrt{1 \times 10^{-4}}\) \(=0.01\)
\(\alpha=\frac{\text { Percent dissociation }}{100} \)
\( \text { Percent dissociation }=\alpha \times 100 \)
\( =0.01 \times 100=1.0 \%\)