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MHT CET · Chemistry · Solutions

Vapour pressure of solvent 'A' is \(0.90 \mathrm{~atm}\), when a non volatile solute is added, vapour pressure drops to \(0.60 \mathrm{~atm}\), what is mole fraction of \(\mathrm{A}\) in solution?

  1. A 0.3
  2. B 0.333
  3. C 0.5
  4. D 0.667
Verified Solution

Answer & Solution

Correct Answer

(D) 0.667

Step-by-step Solution

Detailed explanation

\(
\begin{array}{l}
\frac{P_{0}-P}{P_{0}}=x_{2} \\
\frac{0.9-0.6}{0.9}=0.333
\end{array}
\)
Now, \(x_{1}+x_{2}=1\)
\(
\therefore \quad x_{1}=1-x_{2}=1-0.333=0.667
\)