MHT CET · Chemistry · Thermodynamics (C)

Under similar conditions enthalpy of freezing is exactly opposite to

A enthalpy of fusion
B enthalpy of vaporization
C enthalpy of solution
D enthalpy of atomization

Verified Solution

Answer & Solution

Correct Answer

(A) enthalpy of fusion

Step-by-step Solution

Detailed explanation

For the reaction, \(\mathrm{H}_2 \mathrm{O}_{(\mathrm{s})} [\text { freezing }]{\text { fusion }} \mathrm{H}_2 \mathrm{O}_{(\mathrm{l})}\)
Under similar conditions of \(0^{\circ} \mathrm{C}\) and 1 atm pressure, \(\Delta_{\mathrm{fus}} \mathrm{H}\) is \(+6.01 \mathrm{~kJ} \mathrm{~mol}^{-1}\), whereas \(\Delta_{\text {free }} \mathrm{H}\) is \(-6.01 \mathrm{~kJ} \mathrm{~mol}^{-1}\). Thus, enthalpy of freezing is exactly opposite to enthalpy of fusion.

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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