MHT CET · Chemistry · States of Matter
The volume of a gas at \(0^{\circ} \mathrm{C}\) is \(2 \mathrm{dm}^3\). What is its volume if temperature is decreased by \(272^{\circ} \mathrm{C}\) ?
- A \(\left(\frac{3}{272}\right) \mathrm{dm}^3\)
- B \(\left(\frac{2}{272}\right) \mathrm{dm}^3\)
- C \(\left(\frac{4}{273}\right) \mathrm{dm}^3\)
- D \(\left(\frac{2}{273}\right) \mathrm{dm}^3\)
Answer & Solution
Correct Answer
(D) \(\left(\frac{2}{273}\right) \mathrm{dm}^3\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \mathrm{V}_1=2 \mathrm{dm}^3 \\ & \mathrm{~T}_1=273 \mathrm{~K} \\ & \mathrm{~T}_2=273-272=1 \mathrm{~K} \\ & \mathrm{~V}_2=? \\ & \frac{\mathrm{V}_1}{\mathrm{~T}_1}=\frac{\mathrm{V}_2}{\mathrm{~T}_2} \\ & \frac{2}{273}=\frac{\mathrm{V}_2}{1} \\ & \mathrm{~V}_2=\frac{2}{273} \mathrm{dm}^3\end{aligned}\)
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