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MHT CET · Chemistry · Ionic Equilibrium

The solubility product of \(\mathrm{PbI}_2\) is \(1.08 \times 10^{-7}\). Calculate its solubility in \(\mathrm{mol~} \mathrm{dm}^{-3}\) at 298 K ?

  1. A \(2.018 \times 10^{-3}\)
  2. B \(2.011 \times 10^{-9}\)
  3. C \(1.259 \times 10^{-9}\)
  4. D \(3.0 \times 10^{-3}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(3.0 \times 10^{-3}\)

Step-by-step Solution

Detailed explanation

\( K_{sp} = [\mathrm{Pb}^{2+}][\mathrm{I}^{-}]^2 \) \( K_{sp} = (s)(2s)^2 = 4s^3 \)