MHT CET · Chemistry · Ionic Equilibrium
The solubility product of NiS is \(4.9 \times 10^{-5}\) at 298 K. Calculate its solubility in \(\mathrm{mol~} \mathrm{dm}^{-3}\) at the same temperature?
- A \(1.69 \times 10^{-3}\)
- B \(7.0 \times 10^{-3}\)
- C \(2.45 \times 10^{-3}\)
- D \(6.18 \times 10^{-3}\)
Answer & Solution
Correct Answer
(B) \(7.0 \times 10^{-3}\)
Step-by-step Solution
Detailed explanation
\(K_{sp} = s^2\) \(s = \sqrt{K_{sp}}\)
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