MHT CET · Chemistry · Ionic Equilibrium
The solubility product of AgBr is \(4.9 \times 10^{-13}\) at a certain temperature. Calculate the solubility .
- A \(4 \times 10^{-6} \mathrm{~mol~} \mathrm{dm}^{-3}\)
- B \(4 \times 10^{-7} \mathrm{~mol~} \mathrm{dm}^{-3}\)
- C \(7 \times 10^{-7} \mathrm{~mol~} \mathrm{dm}^{-3}\)
- D \(3 \times 10^{-8} \mathrm{~mol~} \mathrm{dm}^{-3}\)
Answer & Solution
Correct Answer
(C) \(7 \times 10^{-7} \mathrm{~mol~} \mathrm{dm}^{-3}\)
Step-by-step Solution
Detailed explanation
\( K_{sp} = s^2 \) \( s = \sqrt{K_{sp}} \)
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