ExamBro
ExamBro
MHT CET · Chemistry · Ionic Equilibrium

The solubility product of \(\mathrm{Ag}_{2} \mathrm{CrO}_{4}\) is \(32 \times 10^{-12}\). What is the concentration of \(\mathrm{CrO}_{4}^{2-}\) ions in that solution?

  1. A \(2 \times 10^{-4}\)
  2. B \(16 \times 10^{-4}\)
  3. C \(8 \times 10^{-4}\)
  4. D \(12 \times 10^{-4}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(2 \times 10^{-4}\)

Step-by-step Solution

Detailed explanation

\(\mathrm{Ag}_{2} \mathrm{CrO}_{4} \longrightarrow 2 \mathrm{Ag}^{+}+\mathrm{CrO}_{4}^{2-} \) \( 2 s \)
\( K_{\mathrm{sp}} =\left[\mathrm{Ag}^{+}\right]^{2}\left[\mathrm{CrO}_{4}^{2-}\right] \)
\( =(2 s)^{2}(s) \)
\( K_{\mathrm{sp}} =4 s^{3} \)
\( s =\left(\frac{K_{\mathrm{sp}}}{4}\right)^{1 / 3} \)
\( =\left(\frac{32 \times 10^{-12}}{4}\right)^{1 / 3} \)
\( =2 \times 10^{-4} \mathrm{M}\)