MHT CET · Chemistry · Ionic Equilibrium
The solubility product of a sparingly soluble salt \(\mathrm{AX}_2\) is \(3.2 \times 10^{-8}\). What is it's solubility in \(\mathrm{mol} \mathrm{dm}^{-3}\)
- A \(2.8 \times 10^{-4}\)
- B \(1.6 \times 10^{-5}\)
- C \(2.0 \times 10^{-3}\)
- D \(4.0 \times 10^{-4}\)
Answer & Solution
Correct Answer
(C) \(2.0 \times 10^{-3}\)
Step-by-step Solution
Detailed explanation

\(\begin{aligned} & \mathrm{Ksp}=\left[\mathrm{A}^{2+}\right]\left[\mathrm{X}^{-}\right]^2 \\ & =\mathrm{S}(2 \mathrm{~S})^2 \\ & =4 \mathrm{~S}^3 \\ & 3.2 \times 10^{-8} 4 \mathrm{~S}^3 \\ & \mathrm{~S}^3=\frac{32}{4} \times 10^{-9}=8 \times 10^{-9} \\ & \mathrm{~S}=2 \times 10^{-3} \mathrm{~mol} . \mathrm{dm}^{-3} \text {. } \\ & \end{aligned}\)
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