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MHT CET · Chemistry · Ionic Equilibrium

The solubility of sparingly soluble salt \(\mathrm{AX}_2\) is \(1 \times 10^{-4} \mathrm{~mol~} \mathrm{dm}^{-3}\) at 298 K . Calculate its solubility product?

  1. A \(2 \times 10^{-12}\)
  2. B \(4 \times 10^{-12}\)
  3. C \(2 \times 10^{-10}\)
  4. D \(4 \times 10^{-10}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(4 \times 10^{-12}\)

Step-by-step Solution

Detailed explanation

\(K_{sp} = 4s^3\) \(K_{sp} = 4 \times (1 \times 10^{-4})^3\)