MHT CET · Chemistry · Ionic Equilibrium
The solubility of sparingly soluble salt \(\mathrm{AX}_2\) is \(1 \times 10^{-4} \mathrm{~mol~} \mathrm{dm}^{-3}\) at 298 K . Calculate its solubility product?
- A \(2 \times 10^{-12}\)
- B \(4 \times 10^{-12}\)
- C \(2 \times 10^{-10}\)
- D \(4 \times 10^{-10}\)
Answer & Solution
Correct Answer
(B) \(4 \times 10^{-12}\)
Step-by-step Solution
Detailed explanation
\(K_{sp} = 4s^3\) \(K_{sp} = 4 \times (1 \times 10^{-4})^3\)
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