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MHT CET · Chemistry · Solutions

The solubility of \(\mathrm{CaCO}_3\) is \(7 \times 10^{-5} \mathrm{~mol} \mathrm{dm}^{-3}\) at \(25^{\circ} \mathrm{C}\). What is its solubility product at same temperature?

  1. A \(6.7 \times 10^{-9}\)
  2. B \(9.0 \times 10^{-9}\)
  3. C \(1.12 \times 10^{-9}\)
  4. D \(4.9 \times 10^{-9}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(4.9 \times 10^{-9}\)

Step-by-step Solution

Detailed explanation

\(\mathrm{CaCO}_{3(\mathrm{~s})} \rightleftharpoons \mathrm{Ca}_{(\mathrm{aq})}^{2+}+\mathrm{CO}_{3(\text { aq })}^{2-} \)
\( x=1, \mathrm{y}=1 \)
\( \mathrm{~K}_{\mathrm{sp}}=x^x \mathrm{y}^{\mathrm{y}} \mathrm{S}^{(x+\mathrm{y})}\) \(=(1)^1(1)^1 \mathrm{~S}^{1+1}=\mathrm{S}^2 \)
\( \therefore \mathrm{~K}_{\mathrm{sp}}=\left(7 \times 10^{-5}\right)^2=49 \times 10^{-10}\) \(=4.9 \times 10^{-9}\)