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MHT CET · Chemistry · Ionic Equilibrium

The solubility of AgBr is \(7.1 \times 10^{-7} \mathrm{~mol~} \mathrm{dm}^{-3}\). Calculate it's solubility product at the same temperature.

  1. A \(7.08 \times 10^{-13}\)
  2. B \(3.67 \times 10^{-13}\)
  3. C \(5.89 \times 10^{-13}\)
  4. D \(5.04 \times 10^{-13}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(5.04 \times 10^{-13}\)

Step-by-step Solution

Detailed explanation

\(K_{sp} = s^2\) \(K_{sp} = (7.1 \times 10^{-7})^2 = 5.041 \times 10^{-13}\)