MHT CET · Chemistry · Chemical Kinetics
The slope of a graph \(\log [A]_t\) versus ' \(t\) ' for first order reaction is \(-2.5 \times 10^{-3} \mathrm{~s}^{-1}\). Find rate constant of the reaction?
- A \(1.263 \times 10^{-3} \mathrm{~s}^{-1}\)
- B \(3.471 \times 10^{-3} \mathrm{~s}^{-1}\)
- C \(5.757 \times 10^{-3} \mathrm{~s}^{-1}\)
- D \(8.125 \times 10^{-3} \mathrm{~s}^{-1}\)
Answer & Solution
Correct Answer
(C) \(5.757 \times 10^{-3} \mathrm{~s}^{-1}\)
Step-by-step Solution
Detailed explanation
\(\text{Slope} = -\frac{k}{2.303}\) \(k = - \text{Slope} \times 2.303\)
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