MHT CET · Chemistry · Electrochemistry

The resistance of conductivity cell filled with 0.1 M KCl solution is 100 ohm and conductivity is \(1.70 \times 10^{-4} \mathrm{~S} \mathrm{~cm}^{-1}\). What is the cell constant of the cell?

A \(1.70 \mathrm{~cm}^{-1}\)
B \(0.017 \mathrm{~cm}^{-1}\)
C \(0.058 \mathrm{~cm}^{-1}\)
D \(0.012 \mathrm{~cm}^{-1}\)

Verified Solution

Answer & Solution

Correct Answer

(B) \(0.017 \mathrm{~cm}^{-1}\)

Step-by-step Solution

Detailed explanation

\(G^*=\kappa \times R\)
Where:
- \(G^*\) is the cell constant \(\left(\mathrm{cm}^{-1}\right)\),
- \(\kappa\) is the conductivity \(\left(\mathrm{S} \mathrm{cm}^{-1}\right)\),
- \(R\) is the resistance \((\Omega)\).
Given:
- \(\kappa=1.70 \times 10^{-4} \mathrm{~S} \mathrm{~cm}^{-1}\),
- \(R=100 \Omega\).
Calculation:
\(G^*=\left(1.70 \times 10^{-4}\right) \times 100=0.017 \mathrm{~cm}^{-1}\)
Final Answer:
The cell constant is:
\(0.017 \mathrm{~cm}^{-1}\)
Hence, the correct option is (2) \(0.017 \mathrm{~cm}^{-1}\).

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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