MHT CET · Chemistry · Chemical Kinetics
The rate law for a reaction between reactants \(A, B\) and \(C\) is \(r=K[A][B][C]^2\), if concentration of \(A\) is halved, then rate of reaction
- A increase \(\frac{1}{2}\) times
- B remains the same
- C decreases \(\frac{1}{2}\) times
- D increase 2 times
Answer & Solution
Correct Answer
(C) decreases \(\frac{1}{2}\) times
Step-by-step Solution
Detailed explanation
\(\mathrm{r}=\mathrm{K}[\mathrm{A}][\mathrm{B}][\mathrm{C}]^2\) of canc. of \(\mathrm{A}\) is halved
\(\mathrm{r}=\mathrm{K} \frac{[\mathrm{A}]}{2}[\mathrm{~B}][\mathrm{C}]^2\)
\(\mathrm{r}=\mathrm{K} \frac{[\mathrm{A}]}{2}[\mathrm{~B}][\mathrm{C}]^2\)
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