MHT CET · Chemistry · Chemical Kinetics
The rate constant for a first order reaction is \(0.58 \mathrm{~s}^{-1}\) at 300 K and \(0.026 \mathrm{~s}^{-1}\) at 290 K. What is the energy of activation? \(\left(\mathrm{R}=8.314 \mathrm{~J} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}\right)\)
- A \(124 \cdot 48 \mathrm{~kJ}\)
- B \(224 \cdot 55 \mathrm{~kJ}\)
- C \(348 \cdot 18 \mathrm{~kJ}\)
- D \(513 \cdot 21 \mathrm{~kJ}\)
Answer & Solution
Correct Answer
(B) \(224 \cdot 55 \mathrm{~kJ}\)
Step-by-step Solution
Detailed explanation
\( \ln \left( \frac{k_2}{k_1} \right) = \frac{E_a}{R} \left( \frac{1}{T_1} - \frac{1}{T_2} \right) \) \( \ln \left( \frac{0.58}{0.026} \right) = \frac{E_a}{8.314} \left( \frac{1}{290} - \frac{1}{300} \right) \)
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