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MHT CET · Chemistry · Ionic Equilibrium

The pH of monoacidic base is 10 . Calculate its percentage dissociation in 0.01 M solution at 298 K ?

  1. A \(10 \%\)
  2. B \(5 \%\)
  3. C \(2 \%\)
  4. D \(1 \%\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(1 \%\)

Step-by-step Solution

Detailed explanation

\(pOH = 14 - pH = 14 - 10 = 4\) \([OH^-] = 10^{-pOH} = 10^{-4} M\)