MHT CET · Chemistry · Ionic Equilibrium
The pH of monoacidic base is 10 . Calculate its percentage dissociation in 0.01 M solution at 298 K ?
- A \(10 \%\)
- B \(5 \%\)
- C \(2 \%\)
- D \(1 \%\)
Answer & Solution
Correct Answer
(D) \(1 \%\)
Step-by-step Solution
Detailed explanation
\(pOH = 14 - pH = 14 - 10 = 4\) \([OH^-] = 10^{-pOH} = 10^{-4} M\)
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