MHT CET · Chemistry · Ionic Equilibrium
The pH of a sample of vinegar is 3.76. Calculate the concentration of hydrogen ion in it in \(\mathrm{mol~} \mathrm{dm}^{-3}\) ?
- A \(1.97 \times 10^{-4}\)
- B \(1.738 \times 10^{-4}\)
- C \(1.84 \times 10^{-4}\)
- D \(1.283 \times 10^{-4}\)
Answer & Solution
Correct Answer
(B) \(1.738 \times 10^{-4}\)
Step-by-step Solution
Detailed explanation
\([\mathrm{H}^{+}] = 10^{-\mathrm{pH}}\) \([\mathrm{H}^{+}] = 10^{-3.76}\)
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