MHT CET · Chemistry · Chemical Equilibrium
The percent dissociation of weak monobasic acid is \(3 \%\) in its \(0.02 \mathrm{M}\) solution. What is the dissociation constant of acid?
- A \(9 \times 10^{-4}\)
- B \(3 \times 10^{-2}\)
- C \(2 \times 10^{-2}\)
- D \(1.8 \times 10^{-5}\)
Answer & Solution
Correct Answer
(D) \(1.8 \times 10^{-5}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & K_a=\propto^2 C \\ & =\left(\frac{3}{100}\right)^2 \times 0.02 \\ & =1.8 \times 10^{-5}\end{aligned}\)
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