MHT CET · Chemistry · d and f Block Elements
The oxidation state of \(\mathrm{Cr}\) in \(\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}\) is
- A \(+4\)
- B \(+3\)
- C \(+6\)
- D \(+5\)
Answer & Solution
Correct Answer
(C) \(+6\)
Step-by-step Solution
Detailed explanation
\(\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}\)
Let the oxidation state of \(\mathrm{Cr}\) is \(x\).
\(
\begin{aligned}
2(+1)+2 x+7(-2) &=0 \\
+2+2 x-14 &=0 \\
2 x-12 &=0 \\
x &=+6
\end{aligned}
\)
Let the oxidation state of \(\mathrm{Cr}\) is \(x\).
\(
\begin{aligned}
2(+1)+2 x+7(-2) &=0 \\
+2+2 x-14 &=0 \\
2 x-12 &=0 \\
x &=+6
\end{aligned}
\)
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