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The molarity of urea (molar mass $60 g m o l^{- 1}$ ) solution obtained by dissolving $15 g$ of urea in $500 c m^{3}$ of water is

A $2 m o l d m^{- 3}$
B $0.5 m o l d m^{- 3}$
C $0.125 m o l d m^{- 3}$
D $0.0005 m o l d m^{- 3}$

Verified Solution

Answer & Solution

Correct Answer

(B) $0.5 m o l d m^{- 3}$

Step-by-step Solution

Detailed explanation

Urea molar mass

= 60 g / mol

molarity = \frac{15 \times 1000}{60 \times 500} = \frac{15}{6 \times 5} = \frac{1}{2}

= 0.5 mol {dm}^{- 3}

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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The molarity of urea (molar mass 60 g mol-1) solution obtained by dissolving 15 g of urea in 500 cm3 of water is

Step-by-step Solution

The molarity of urea (molar mass $60 g m o l^{- 1}$ ) solution obtained by dissolving $15 g$ of urea in $500 c m^{3}$ of water is