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MHT CET · Chemistry · Electrochemistry

The molar conductivity of 0.01 M acetic acid at \(25^{\circ} \mathrm{C}\) is \(16.5 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}\) and its molar conductivity at zero concentration is \(390: 7 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}\). What is its degree of dissociation?

  1. A 0.0223
  2. B 0.0422
  3. C 0.0642
  4. D 0.0821
Verified Solution

Answer & Solution

Correct Answer

(B) 0.0422

Step-by-step Solution

Detailed explanation

\(\alpha=\frac{16.5 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}}{390.7 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}}=0.0422\)