MHT CET · Chemistry · Electrochemistry
The molar conductivity of 0.01 M acetic acid at \(25^{\circ} \mathrm{C}\) is \(16.5 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}\) and its molar conductivity at zero concentration is \(390: 7 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}\). What is its degree of dissociation?
- A 0.0223
- B 0.0422
- C 0.0642
- D 0.0821
Answer & Solution
Correct Answer
(B) 0.0422
Step-by-step Solution
Detailed explanation
\(\alpha=\frac{16.5 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}}{390.7 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}}=0.0422\)
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