MHT CET · Chemistry · Ionic Equilibrium
The increasing order of \(\mathrm{PH}^{\mathrm{H}}\) of \(0.1 \mathrm{M}\) solution of the following compounds is
- A \(\mathrm{HCl}<\mathrm{NaCl}<\mathrm{NaCN}<\mathrm{NH}_4 \mathrm{NO}_3\)
- B \(\mathrm{NH}_4 \mathrm{ON}_3<\mathrm{HCl}<\mathrm{NaCl}<\mathrm{NaCH}\)
- C \(\mathrm{BaCN}<\mathrm{HCl} \mathrm{NH}{ }_4 \mathrm{NO}_3<\mathrm{HCl}\)
- D \(\mathrm{HCl}<\mathrm{NH}_4 \mathrm{NO}_3<\mathrm{NaCl}<\mathrm{NaCN}\)
Answer & Solution
Correct Answer
(D) \(\mathrm{HCl}<\mathrm{NH}_4 \mathrm{NO}_3<\mathrm{NaCl}<\mathrm{NaCN}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{HCl}\) (SA), \(\mathrm{NH}_4 \mathrm{NO}_3\) (SAWB), \(\mathrm{NaCl}(\mathrm{SASB}) \mathrm{NaCN}\) (WASB)
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