MHT CET · Chemistry · Ionic Equilibrium
The hydrolysis of sodium carbonate involves the reaction between
- A sodium ion and water
- B \(\mathrm{Na}^{+}\) and \(\mathrm{OH}^{-}\)
- C \(\mathrm{CO}_{3}^{2-}\) and water
- D \(\mathrm{CO}_{3}^{2-}\) and \(\mathrm{H}^{+}\)
Answer & Solution
Correct Answer
(C) \(\mathrm{CO}_{3}^{2-}\) and water
Step-by-step Solution
Detailed explanation
\(\mathrm{Na}_{2} \mathrm{CO}_{3}+2 \mathrm{H}_{2} \mathrm{O} \rightleftharpoons 2 \mathrm{NaOH}+\mathrm{H}_{2} \mathrm{CO}_{3} \)
\( \text { or } 2 \mathrm{Na}^{+}+\mathrm{CO}_{3}^{2-}+2 \mathrm{H}_{2} \mathrm{O} \)
\( \rightleftharpoons 2 \mathrm{Na}^{+}+2 \mathrm{OH}^{-}+\mathrm{H}_{2} \mathrm{CO}_{3} \)
\( \text { or } \mathrm{CO}_{3}^{2-}+2 \mathrm{H}_{2} \mathrm{O} \rightleftharpoons 2 \mathrm{OH}^{-}+\mathrm{H}_{2} \mathrm{CO}_{3}\)
It is anionic hydrolysis.
\( \text { or } 2 \mathrm{Na}^{+}+\mathrm{CO}_{3}^{2-}+2 \mathrm{H}_{2} \mathrm{O} \)
\( \rightleftharpoons 2 \mathrm{Na}^{+}+2 \mathrm{OH}^{-}+\mathrm{H}_{2} \mathrm{CO}_{3} \)
\( \text { or } \mathrm{CO}_{3}^{2-}+2 \mathrm{H}_{2} \mathrm{O} \rightleftharpoons 2 \mathrm{OH}^{-}+\mathrm{H}_{2} \mathrm{CO}_{3}\)
It is anionic hydrolysis.
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