MHT CET · Chemistry · Thermodynamics (C)
The heat of Combustion of acetaldehyde to carbon dioxide and water is \(-1172 \mathrm{~kJ}\) \(\mathrm{mol}^{-1}\). Calculate amount of heat liberated when \(66 \mathrm{~g}\) of acetaldehyde were completely oxidised ? (at. mass \(\mathrm{C}=12, \mathrm{H}=1,0=16\) )
- A \(1758 \mathrm{~kJ}\)
- B \(2344 \mathrm{~kJ}\)
- C \(6600 \mathrm{~kg}\)
- D \(1172 \mathrm{~kJ}\)
Answer & Solution
Correct Answer
(A) \(1758 \mathrm{~kJ}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{CH}_{3} \mathrm{CHO}+2.5 \mathrm{O}_{2} \longrightarrow 2 \mathrm{CO}_{2}+2 \mathrm{H}_{2} \mathrm{O} \quad \Delta \mathrm{H}\)\(=-1172 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
For \(44 \mathrm{~g}\) of \(\mathrm{CH}_{3} \mathrm{CHO}, \Delta \mathrm{H}=-1172 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
\(\therefore 66 \mathrm{~g}\) of \(\mathrm{CH}_{3} \mathrm{CHO}, \Delta \mathrm{H}=\frac{-1172 \times 66}{44}=-1758 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
\(\therefore\) The amount of heat liberated when \(66 \mathrm{~g}\) of acetaldehyde were completely oxidised is \(1758 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
For \(44 \mathrm{~g}\) of \(\mathrm{CH}_{3} \mathrm{CHO}, \Delta \mathrm{H}=-1172 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
\(\therefore 66 \mathrm{~g}\) of \(\mathrm{CH}_{3} \mathrm{CHO}, \Delta \mathrm{H}=\frac{-1172 \times 66}{44}=-1758 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
\(\therefore\) The amount of heat liberated when \(66 \mathrm{~g}\) of acetaldehyde were completely oxidised is \(1758 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
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