MHT CET · Chemistry · Amines
The end product \(\mathrm{C}\) of the following reaction is \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{NH}_{2} \stackrel{\mathrm{HNO}_{2}}{\longrightarrow} \mathrm{A} \stackrel{\mathrm{PCl}_{5}}{\longrightarrow} \mathrm{B} \frac{\mathrm{NH}_{3}}{\text { alcohol }} \longrightarrow \mathrm{C}\)
- A Ethanol
- B Ethanamine
- C Chloroethane
- D Nitroethane
Answer & Solution
Correct Answer
(B) Ethanamine
Step-by-step Solution
Detailed explanation
(B)
\(C _2 H _5 NH _2 \xrightarrow{ HNO _2} C _2 H _5 OH \xrightarrow{ PCl _5} C _2 H _5 Cl\) \(\xrightarrow[\text { alcohol }]{ NH _3} C _2 H _5 NH _2\)
Ethanamine\(\qquad\quad~\)Ethanol (A)\(\qquad\)Chloroethane (B)\(\quad\)Ethanamine (C)
\(C _2 H _5 NH _2 \xrightarrow{ HNO _2} C _2 H _5 OH \xrightarrow{ PCl _5} C _2 H _5 Cl\) \(\xrightarrow[\text { alcohol }]{ NH _3} C _2 H _5 NH _2\)
Ethanamine\(\qquad\quad~\)Ethanol (A)\(\qquad\)Chloroethane (B)\(\quad\)Ethanamine (C)
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