MHT CET · Chemistry · Solid State
The edge length of fcc type unit cell of copper having atomic radius \(127.6 \mathrm{pm}\) is equal to
- A \(295 \mathrm{pm}\)
- B 361 pm
- C \(331 \mathrm{pm}\)
- D \(378 \mathrm{pm}\)
Answer & Solution
Correct Answer
(B) 361 pm
Step-by-step Solution
Detailed explanation
For fcc type unit cell
\(\mathrm{r}=\frac{\mathrm{a}}{2 \sqrt{2}} \quad \therefore \mathrm{a}=\mathrm{r}(2 \sqrt{2})=127.6(2 \sqrt{2})\)\(=360.85 \approx 361 \mathrm{pm}\)
\(\mathrm{r}=\frac{\mathrm{a}}{2 \sqrt{2}} \quad \therefore \mathrm{a}=\mathrm{r}(2 \sqrt{2})=127.6(2 \sqrt{2})\)\(=360.85 \approx 361 \mathrm{pm}\)
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