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MHT CET · Chemistry · Electrochemistry

The distance between electrodes of a conductivity cell is \(0.98 \mathrm{~cm}\) and area of cross section is \(1.96 \mathrm{~cm}^{2} .\) What is the cell constant?

  1. A \(1 \mathrm{~cm}^{-1}\)
  2. B \(1.5 \mathrm{~cm}^{-1}\)
  3. C \(2 \mathrm{~cm}^{-1}\)
  4. D \(0.5 \mathrm{~cm}^{-1}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(0.5 \mathrm{~cm}^{-1}\)

Step-by-step Solution

Detailed explanation

(C)
Cell constant, \(\mathrm{b}=\frac{\ell}{\mathrm{a}}=\frac{0.98 \mathrm{~cm}}{1.96 \mathrm{~cm}^{2}}=0.5 \mathrm{~cm}^{-1}\)