MHT CET · Chemistry · Electrochemistry
The distance between electrodes of a conductivity cell is \(0.98 \mathrm{~cm}\) and area of cross section is \(1.96 \mathrm{~cm}^{2} .\) What is the cell constant?
- A \(1 \mathrm{~cm}^{-1}\)
- B \(1.5 \mathrm{~cm}^{-1}\)
- C \(2 \mathrm{~cm}^{-1}\)
- D \(0.5 \mathrm{~cm}^{-1}\)
Answer & Solution
Correct Answer
(D) \(0.5 \mathrm{~cm}^{-1}\)
Step-by-step Solution
Detailed explanation
(C)
Cell constant, \(\mathrm{b}=\frac{\ell}{\mathrm{a}}=\frac{0.98 \mathrm{~cm}}{1.96 \mathrm{~cm}^{2}}=0.5 \mathrm{~cm}^{-1}\)
Cell constant, \(\mathrm{b}=\frac{\ell}{\mathrm{a}}=\frac{0.98 \mathrm{~cm}}{1.96 \mathrm{~cm}^{2}}=0.5 \mathrm{~cm}^{-1}\)
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