MHT CET · Chemistry · Ionic Equilibrium
The dissociation constant of a weak monobasic acid is \(3.2 \times 10^{-4}\). Calculate the degree of dissociation in its 0.04 M solution.
- A 0.0128
- B 0.0151
- C 0.078
- D 0.089
Answer & Solution
Correct Answer
(D) 0.089
Step-by-step Solution
Detailed explanation
\(\mathrm{K}_{\mathrm{a}}=3.2 \times 10^{-4} ; \mathrm{c}=0.04 \mathrm{M}\)
For a monobasic acid,
\(\alpha=\sqrt{\frac{K_a}{c}}=\sqrt{\frac{3.2 \times 10^{-4}}{0.04}}=\sqrt{8 \times 10^{-3}}=0.089\)
For a monobasic acid,
\(\alpha=\sqrt{\frac{K_a}{c}}=\sqrt{\frac{3.2 \times 10^{-4}}{0.04}}=\sqrt{8 \times 10^{-3}}=0.089\)
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