MHT CET · Chemistry · Solid State
The density of chromium metal is \(7 \mathrm{~g} \mathrm{~cm}^{-3}\). If edge length of unit cell is \(300 \mathrm{pm}\), identify the type of unit cell. (At. mass \(\mathrm{Cr}=52\) )
- A Body centred cubic
- B Simple cubic
- C Hexagonal close pack
- D Face centred cubic
Answer & Solution
Correct Answer
(A) Body centred cubic
Step-by-step Solution
Detailed explanation
\(\begin{aligned}
& \mathrm{d}=\frac{\mathrm{ZM}}{\mathrm{N}_{\mathrm{A}} \mathrm{a}^3} \\
& \mathrm{Z}=\frac{\mathrm{d} \cdot \mathrm{N}_{\mathrm{A}} \cdot \mathrm{a}^3}{\mathrm{M}} \\
& \mathrm{a}=300 \mathrm{pm} \\
& \mathrm{a}=300 \times 10^{-10} \mathrm{~cm} \\
& \mathrm{a}=3 \times 10^{-8} \mathrm{~cm} \\
& =\frac{7 \times 6.022 \times 10^{23} \times\left(3 \times 10^{-8}\right)^3}{52}
\end{aligned}\)
Unit cell is Body centred cubic
& \mathrm{d}=\frac{\mathrm{ZM}}{\mathrm{N}_{\mathrm{A}} \mathrm{a}^3} \\
& \mathrm{Z}=\frac{\mathrm{d} \cdot \mathrm{N}_{\mathrm{A}} \cdot \mathrm{a}^3}{\mathrm{M}} \\
& \mathrm{a}=300 \mathrm{pm} \\
& \mathrm{a}=300 \times 10^{-10} \mathrm{~cm} \\
& \mathrm{a}=3 \times 10^{-8} \mathrm{~cm} \\
& =\frac{7 \times 6.022 \times 10^{23} \times\left(3 \times 10^{-8}\right)^3}{52}
\end{aligned}\)
Unit cell is Body centred cubic
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