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MHT CET · Chemistry · Electrochemistry

The conductivity of \(0.3 \mathrm{M}\) solution of \(\mathrm{KCl}\) at \(298 \mathrm{~K}\) is \(0.0627 \mathrm{~S} \mathrm{~cm}^1\). What is its molar conductivity?

  1. A \(104 \mathrm{~S} \mathrm{~cm}^2 \mathrm{~mol}^{-1}\)
  2. B \(188 \mathrm{~S} \mathrm{~cm}^2 \mathrm{~mol}^{-1}\)
  3. C \(209 \mathrm{~S} \mathrm{~cm}^2 \mathrm{~mol}^{-1}\)
  4. D \(109 \mathrm{~S} \mathrm{~cm}^2 \mathrm{~mol}^{-1}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(209 \mathrm{~S} \mathrm{~cm}^2 \mathrm{~mol}^{-1}\)

Step-by-step Solution

Detailed explanation

\(\begin{aligned} & \Lambda_{\mathrm{m}}=\frac{\mathrm{k} \times 1000}{\mathrm{M}} \\ & \mathrm{k}=0.0627 \mathrm{~S} \mathrm{~cm}^1 \\ & \mathrm{M}=0.3 \\ & =\frac{0.0627 \times 1000}{0.3} \\ & =209 \mathrm{~S} \mathrm{~cm}^2 \mathrm{~mol}^{-1}\end{aligned}\)