MHT CET · Chemistry · Electrochemistry
The conductivity of 0.02 M solution of \(\mathrm{AgNO}_3\) is \(0.00216 \Omega^{-1} \mathrm{~cm}^{-1}\) at 298 K . What is its molar conductivity?
- A \(232.0 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}\)
- B \(402.0 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}\)
- C \(108.0 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}\)
- D \(150.0 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}\)
Answer & Solution
Correct Answer
(C) \(108.0 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}\)
Step-by-step Solution
Detailed explanation
\(\Lambda =\frac{1000 \mathrm{k}}{\mathrm{c}}=\frac{1000 \mathrm{~cm}^3 \mathrm{L}^{-1} \times 0.00216 \Omega^{-1} \mathrm{~cm}^{-1}}{0.02 \mathrm{~mol} \mathrm{~L}^{-1}}\)
\(=108.0 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}\)
\(=108.0 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}\)
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