MHT CET · Chemistry · Chemical Kinetics
The calculated mass of \({ }_{20} \mathrm{Ca}^{40}\) is \(40.328 \mathrm{u}\). It releases \(306.3 \mathrm{MeV}\) energy in a nuclear process. Its isotopic mass is
- A \(39.998\)
- B \(40.6570\)
- C \(0.3290\)
- D \(2.85 \times 10^{4}\)
Answer & Solution
Correct Answer
(A) \(39.998\)
Step-by-step Solution
Detailed explanation
\(\mathrm{BE}=\Delta m \times 931 \mathrm{MeV}\)
\(306.3=\Delta m \times 931\)
\(\Delta m=0.3290\)
\(\Delta m=\) calculated mass \(-\) isotopic mass
- Isotopic mass \(=\Delta m-\) calculated mass
\(= 0.3290-40.328 \)
\( =-39.998 \)
\( \therefore \text { Isotopic mass } =39.998\)
\(306.3=\Delta m \times 931\)
\(\Delta m=0.3290\)
\(\Delta m=\) calculated mass \(-\) isotopic mass
- Isotopic mass \(=\Delta m-\) calculated mass
\(= 0.3290-40.328 \)
\( =-39.998 \)
\( \therefore \text { Isotopic mass } =39.998\)
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