ExamBro
ExamBro
MHT CET · Chemistry · Ionic Equilibrium

Solubility of \(\mathrm{Ca}(\mathrm{OH})_{2}\) is \(s \mathrm{~mol} \mathrm{~L}^{-1}\). The solubility product \(\left(K_{s p}\right)\) under the same condition is

  1. A \(4 s^{3}\)
  2. B \(3 s^{4}\)
  3. C \(4 s^{2}\)
  4. D \(s^{3}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(4 s^{3}\)

Step-by-step Solution

Detailed explanation

\(\begin{aligned} \mathrm{Ca}(\mathrm{OH}) & \rightleftharpoons \mathrm{Ca}^{2+}+2 \mathrm{OH}^{-} \\ K_{s p} &=\left[\mathrm{Ca}^{2+}\right]\left[\mathrm{OH}^{-}\right]^{2} \\ &=(s)(2 s)^{2}=4 s^{3} \end{aligned}\)