MHT CET · Chemistry · Solid State
Sodium crystallizes in bcc structure with radius \(1 \cdot 86 \times 10^{-8} \mathrm{~cm}\). What is the edge length of unit cell of sodium?
- A \(4 \cdot 3 \times 10^{-8} \mathrm{~cm}\)
- B \(3 \cdot 72 \times 10^{-8} \mathrm{~cm}\)
- C \(7 \cdot 44 \times 10^{-8} \mathrm{~cm}\)
- D \(5 \cdot 26 \times 10^{-8} \mathrm{~cm}\)
Answer & Solution
Correct Answer
(A) \(4 \cdot 3 \times 10^{-8} \mathrm{~cm}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned}
r &=1.86 \times 10^{-8} \mathrm{~cm} \\
a &=?
\end{aligned}\)
For bcc structure, \(r=\frac{\sqrt{3}}{4} a\)
\(\begin{array}{l}
\therefore \sqrt{3} \mathrm{a}=4 \mathrm{r} \\
\therefore a=\frac{4 \mathrm{r}}{\sqrt{3}}=\frac{4 \times 1.86 \times 10^{-8} \mathrm{~cm}}{\sqrt{3}} \quad \therefore a=4.3 \times 10^{-8} \mathrm{~cm}
\end{array}\)
r &=1.86 \times 10^{-8} \mathrm{~cm} \\
a &=?
\end{aligned}\)
For bcc structure, \(r=\frac{\sqrt{3}}{4} a\)
\(\begin{array}{l}
\therefore \sqrt{3} \mathrm{a}=4 \mathrm{r} \\
\therefore a=\frac{4 \mathrm{r}}{\sqrt{3}}=\frac{4 \times 1.86 \times 10^{-8} \mathrm{~cm}}{\sqrt{3}} \quad \therefore a=4.3 \times 10^{-8} \mathrm{~cm}
\end{array}\)
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