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MHT CET · Chemistry · Solid State

Silver crystallises in fcc structure, if edge length of unit cell is \(316.5 \mathrm{pm}\). What is the radius of silver atom?

  1. A \(137.04 \mathrm{pm}\)
  2. B \(111.91 \mathrm{pm}\)
  3. C \(121.91 \mathrm{pm}\)
  4. D \(158.25 \mathrm{pm}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(158.25 \mathrm{pm}\)

Step-by-step Solution

Detailed explanation

(B)
\(\mathrm{a}=316.5 \mathrm{pm}\)
For fcc unit cell, \(r=\frac{a}{2 \sqrt{2}}\)
\(\therefore r=\frac{316.5 \mathrm{pm}}{2 \times 1.414}=111.91 \mathrm{pm}\)