MHT CET · Chemistry · Chemical Kinetics
Rate of a first order reaction is \(1.5 \times 10^{-2} \mathrm{~mol} \mathrm{~L}^{-1}\) minute \({ }^{-1}\) at 0.5 M concentration of reactant, calculate half life of reaction.
- A 0.383 minute
- B 7.53 minute
- C 8.73 minute
- D 23.1 minute
Answer & Solution
Correct Answer
(D) 23.1 minute
Step-by-step Solution
Detailed explanation
\(\text {For a } 1^{\text {st }} \text { order reaction, } \)
\( \text { Rate }=\mathrm{k}(\mathrm{A})^1 \)
\( 1.5 \times 10^{-2} \mathrm{~mol} \mathrm{~L}^{-1} \text { minute }^{-1}=\mathrm{k}(0.5 \mathrm{M}) \)
\( \mathrm{k}=0.03 \text { minute }^{-1}\)
\(\therefore \mathrm{t}_{1 / 2}=\frac{0.693}{0.03 \text { minute }^{-1}}=23.1\) minute
\( \text { Rate }=\mathrm{k}(\mathrm{A})^1 \)
\( 1.5 \times 10^{-2} \mathrm{~mol} \mathrm{~L}^{-1} \text { minute }^{-1}=\mathrm{k}(0.5 \mathrm{M}) \)
\( \mathrm{k}=0.03 \text { minute }^{-1}\)
\(\therefore \mathrm{t}_{1 / 2}=\frac{0.693}{0.03 \text { minute }^{-1}}=23.1\) minute
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