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MHT CET · Chemistry · Chemical Kinetics

Rate law for a reaction is \(\mathrm{r}=\mathrm{k}[\mathrm{A}]^2[\mathrm{~B}]\). If rate constant is \(6.25 \mathrm{~mol}^{-2} \mathrm{dm}^6 \mathrm{~s}^{-1}\), what is the rate of reaction when \([\mathrm{A}]=1 \mathrm{~mol} \mathrm{dm}^{-3}\) and \([\mathrm{B}]=0.2 \mathrm{~mol} \mathrm{dm}^{-3}\) ?

  1. A \(1.250 \mathrm{~mol} \mathrm{dm}^{-3} \mathrm{sec}^{-1}\)
  2. B \(2.125 \mathrm{~mol} \mathrm{dm}^{-3} \mathrm{sec}^{-1}\)
  3. C \(3.105 \mathrm{~mol} \mathrm{dm}^{-3} \mathrm{sec}^{-1}\)
  4. D \(2.0 \times 10^{-2} \mathrm{~mol} \mathrm{dm}^{-3} \mathrm{sec}^{-1}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(1.250 \mathrm{~mol} \mathrm{dm}^{-3} \mathrm{sec}^{-1}\)

Step-by-step Solution

Detailed explanation

\(\begin{aligned} & \mathrm{r}=\mathrm{k}[\mathrm{A}]^2[\mathrm{~B}]=6.25 \times(1)^2 \times 0.2 \\ &=6.25 \times 0.2=1.250 \mathrm{~mol} \mathrm{dm}^{-3s}\end{aligned}\)