MHT CET · Chemistry · Chemical Kinetics
Rate law for a reaction is \(\mathrm{r}=\mathrm{k}[\mathrm{A}]^2[\mathrm{~B}]\). If rate constant is \(6.25 \mathrm{~mol}^{-2} \mathrm{dm}^6 \mathrm{~s}^{-1}\), what is the rate of reaction when \([\mathrm{A}]=1 \mathrm{~mol} \mathrm{dm}^{-3}\) and \([\mathrm{B}]=0.2 \mathrm{~mol} \mathrm{dm}^{-3}\) ?
- A \(1.250 \mathrm{~mol} \mathrm{dm}^{-3} \mathrm{sec}^{-1}\)
- B \(2.125 \mathrm{~mol} \mathrm{dm}^{-3} \mathrm{sec}^{-1}\)
- C \(3.105 \mathrm{~mol} \mathrm{dm}^{-3} \mathrm{sec}^{-1}\)
- D \(2.0 \times 10^{-2} \mathrm{~mol} \mathrm{dm}^{-3} \mathrm{sec}^{-1}\)
Answer & Solution
Correct Answer
(A) \(1.250 \mathrm{~mol} \mathrm{dm}^{-3} \mathrm{sec}^{-1}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \mathrm{r}=\mathrm{k}[\mathrm{A}]^2[\mathrm{~B}]=6.25 \times(1)^2 \times 0.2 \\ &=6.25 \times 0.2=1.250 \mathrm{~mol} \mathrm{dm}^{-3s}\end{aligned}\)
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