MHT CET · Chemistry · Chemical Kinetics
Rate law equation for a reaction is \(R=k[x][y]\), rate of reaction doubles when
- A conc. of \(\mathrm{x}\) is kept constant and conc. of \(\mathrm{y}\) is halved
- B conc. of both \(\mathrm{x}\) and \(\mathrm{y}\) is doubled
- C conc. of \(\mathrm{x}\) is doubled and conc. of \(\mathrm{y}\) is kept constant
- D conc. of \(\mathrm{y}\) is doubled and conc. of \(\mathrm{x}\) is halved
Answer & Solution
Correct Answer
(C) conc. of \(\mathrm{x}\) is doubled and conc. of \(\mathrm{y}\) is kept constant
Step-by-step Solution
Detailed explanation
\(\mathrm{r}=\mathrm{k}(\mathrm{x})(\mathrm{y})\)
Of \(\mathrm{x}\) is doubled and \(\mathrm{y}\) remains constant the rate is doubled.
Of \(\mathrm{x}\) is doubled and \(\mathrm{y}\) remains constant the rate is doubled.
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